CS601 Assignment 1 Solution Spring 23 | CS601 Assignment 1 Solution by getready

Q.1 (a) What is the transmission time of a packet sent by a station if the length of the packet is 1 MB and the bandwidth of the channel is 200 Kbps?

 

Solution:

 

To calculate the transmission time of a packet, we can use the formula:

 

Transmission Time = Packet Size / Bandwidth

 

Given that the packet size is 1 MB (1 Megabyte = 1,000,000 bytes) and the bandwidth is 200 Kbps (200 Kilobits per second), we need to convert the units to ensure consistency.

 

1 Megabyte (MB) = 8 Megabits (Mb)

200 Kilobits (Kbps) = 0.2 Megabits (Mbps)

 

Now we can calculate the transmission time:

 

Transmission Time = (Packet Size in bits) / Bandwidth

 

Packet Size in bits = 1 MB * 8 bits/byte = 8 Megabits (Mb)

 

Transmission Time = 8 Megabits / 0.2 Mbps

 

Transmission Time = 40 seconds

 

Therefore, the transmission time of a packet sent by a station with a packet size of 1 MB and a channel bandwidth of 200 Kbps is 40 seconds.

 

 

Q.2 (b)There is a file of size 2 MB. How long does it take to download this file using a 1-Mbps channel?

 

Solution:

 

To calculate the time it takes to download a file, we can use the formula:

 

Download Time = File Size / Download Speed

 

Given that the file size is 2 MB (2 Megabytes = 2,000,000 bytes) and the download speed is 1 Mbps (1 Megabit per second), we need to convert the units to ensure consistency.

 

1 Megabyte (MB) = 8 Megabits (Mb)

1 Megabit (Mbps) = 1,000 Kilobits (Kbps)

 

Now we can calculate the download time:

 

Download Time = (File Size in bits) / Download Speed

 

File Size in bits = 2 MB * 8 bits/byte = 16 Megabits (Mb)

 

Download Time = 16 Megabits / 1 Mbps

 

Download Time = 16 seconds

 

Therefore, it will take 16 seconds to download a file of size 2 MB using a 1 Mbps channel.

 

Q.1 (c) If the bandwidth of the channel is 5 Kbps, how long does it take to send a frame of 100,000 bits out of this device?
 

Solution:

 

To calculate the transmission time of a frame, we can use the formula:

 

Transmission Time = Frame Size / Bandwidth

 

Given that the frame size is 100,000 bits and the channel bandwidth is 5 Kbps (5 Kilobits per second), we need to convert the units to ensure consistency.

 

1 Kilobit (Kbps) = 1,000 bits

 

Now we can calculate the transmission time:

 

Transmission Time = Frame Size / Bandwidth

 

Transmission Time = 100,000 bits / 5 Kbps

 

Transmission Time = 100,000 bits / 5,000 bits per second

 

Transmission Time = 20 seconds

 

Therefore, it will take 20 seconds to send a frame of 100,000 bits through a channel with a bandwidth of 5 Kbps.

To Get More Assignments Click Here

ISL202 Assignment 1 Solution Spring 23      Click Here

Zoo 510 Assignment 1 Solution Spring 23      Click Here

Question No. 2                                                                                                                    

 Identify the proper type of transmission mode for each of the following devices.

Solution:

Device	Transmission Mode
FM Radio	Broadcast
Telephone conversations	Point-to-Point
Video Conferencing	Point-to-Point or Multipoint
TV broadcast	Broadcast
Walkie-Talkie	Point-to-Point or Broadcast (depending on the specific model)